Discussion:
JI Questions about the V7 chord
(too old to reply)
Joey Goldstein
2011-04-05 21:52:16 UTC
Permalink
In a just intonation for a major key I know that on the V7 chord the
frequency ratio between its root and its b7th chord degree ends up being
16:9.

This is a result of tuning the I IV and V chords all to 6:5:4 and the
roots of IV and IV in pure 5ths away from the root of tonic.
When adding the b7 to the V triad, to create a V7 chord, the b7 tone is
the same tone as the root of IV; and the tuning of the root of IV is
based on it being tuned to a pure P5th below the tonic.
It just so happens that the ratio between the root and b7 of V7 winds up
being 16:9.

The freq ratio of the min 3rd interval formed between and the 3rd and
the 5th of V7 is 6:5.
But what is the freq ratio between V7's 5th and its b7?

It seems to me that in a just intonation there will be two sizes of min
3rd interval used within the V7 chord.
Y/N?

It also seems to me that a JI V7 chord will have audible beats, compared
to an harmonic 7th chord tuned to 7:6:5:4 that has no beats, I believe.
Y/N?
(Yes, I know that this ratio is not really used for dom7 chords in
anything other than barbershop vocal music and by roots blues players.)

Is it possible to use a 4 digit frequency ratio (eg. 7:6:5:4) to
describe *all* the intervals in a JI tuned V7 chord?
If so, then what are those digits please?

It can't be 16:13:11:9 because 11:9 does not reduce to 5:4, and 13:11
does not reduce to 6:5 and we know that the V triad is tuned to 6:5:4.
So what would the numbers be?

Thanks in advance.
--
Joey Goldstein
<http://www.joeygoldstein.com>
<http://homepage.mac.com/josephgoldstein/AudioClips/audio.htm>
joegold AT primus DOT ca
Hans Aberg
2011-04-06 08:52:22 UTC
Permalink
Post by Joey Goldstein
In a just intonation for a major key I know that on the V7 chord the
frequency ratio between its root and its b7th chord degree ends up being
16:9.
This is a result of tuning the I IV and V chords all to 6:5:4 and the
roots of IV and IV in pure 5ths away from the root of tonic.
When adding the b7 to the V triad, to create a V7 chord, the b7 tone is
the same tone as the root of IV; and the tuning of the root of IV is
based on it being tuned to a pure P5th below the tonic.
It just so happens that the ratio between the root and b7 of V7 winds up
being 16:9.
The freq ratio of the min 3rd interval formed between and the 3rd and
the 5th of V7 is 6:5.
But what is the freq ratio between V7's 5th and its b7?
It seems to me that in a just intonation there will be two sizes of min
3rd interval used within the V7 chord.
Y/N?
There are different definitions of the Just m7; in addition to 16/9, I
have a Swedish dictionary that gives 9/5.

They differ by a syntonic comma 81/80, the latter is the difference
between the Just M3 5/4 and the Pythagorean M3 81/64. The variations in
Just intonations are typically in terms of this syntonic comma, so it is
good to remember its value.

Now when defining Just intonation major it gets two different major
seconds, but only one minor second:
mj = 16/15
Mj = 10/9 - small Just major
MJ = 9/8 - large Just major
This produces two sharps, from mj to Mj 25/24 and from mj to MJ 135/128.

The interval of P5 3/2 to Just m7 16/9 is 32/27, so this is a Mj 10/9
and a mj 16/15, which is different from the Just minor third 6/5.

So with Just m7 set to 16/9, this is a yes. But with Just m7 9/5, the
distance to P5 3/2 is 6/5, so this is no: then there is only one m3 6/5.

There seems to be no way to unify these differences in a more complex
musical context. Either the musicians will have to play variable pitch
instruments and adjust these differences on the fly intuitively, or on a
fixed pitch instruments, one will have to temper them out, leading to
tunings such as quarter-comma meantone (which sets the M3 to 5/4) or E31.
Post by Joey Goldstein
It also seems to me that a JI V7 chord will have audible beats, compared
to an harmonic 7th chord tuned to 7:6:5:4 that has no beats, I believe.
Y/N?
Yes, in all common tunings, the m7 will have audible beats. If say A 110
Hz and G a m7 above, no matter how G is adjusted by changing the tuning,
there will be beats between the 7th partial of the A and the 4th partial
of the G.

If one wants these partials to line up to get close to 7/4, then the
only way I found was to put it in the diatonic tuning system on the
augmented 6th in a meantone or E31.

The chord 4:5:6:7 is very stable (beatless), but one does not hit it in E12.
Post by Joey Goldstein
(Yes, I know that this ratio is not really used for dom7 chords in
anything other than barbershop vocal music and by roots blues players.)
On variable pitch instruments, one might slip into it, replacing the m7
by a more distant 7/4, though properly, it is a 6+.
Post by Joey Goldstein
Is it possible to use a 4 digit frequency ratio (eg. 7:6:5:4) to
describe *all* the intervals in a JI tuned V7 chord?
If so, then what are those digits please?
Treat ":" like a "," in a list of numbers, with the additional rule that
all numbers in the list may be multiplied or divided by the same number.
This rule says that we are only interested in the proportions (ratios)
between these numbers, not the numbers themselves taken alone.

So the m7 is
1:5/4:3/2:16/9
which I constructed by just writing down M3 5/4 as 1:5/4, now not a
ratio, but two pitches with relative frequency 1 and 5/4. Then fill in
P5 3/2 as 1:...:3/2, and Jm7 16/9 as 1:...:16/9.

Then multiply all numbers with the least common multiple of the
denominators to find the smallest integer reduction. Looking through,
they have the factors 2^2 = 4, and 3^2 = 9. So multiply with 4*9 = 36,
which gives
36:45:54:64
(Scala probably gives this form.)

If you want to find the ratios of all the intervals, use either form -
the one you prefer. In the first form, the intervals of the major triad
1:5/4:3/2 are 1, 5/4, 3/2 and (3/2)/(5/4) = 6/5. The intervals in
relation to Jm7 16/9 are (16/9)/(3/2) = 32/27 and (16/9)/(5/4) = 64/45.

Hans
J.B. Wood
2011-04-06 11:33:39 UTC
Permalink
Post by Joey Goldstein
In a just intonation for a major key I know that on the V7 chord the
frequency ratio between its root and its b7th chord degree ends up being
16:9.
Hi, Joey, and all. The m7 ratio you cited applies to a Pythagorean
tuning (3-limit JI). As this tuning encompasses only 3/2 P5s we end up
with wide 81/64 M3s. A popular (credit Ptolemy & Didymus) 5-limit JI
diatonic tuning historically has been to have just major 4:5:6 triads on
scale degrees I, IV and V. In this tuning we have 5/4 M3s and 6/5 m3s
in addition to 3/2 P5s. If we use a m7 = P5 * m3 to add chromatics to
this tuning, a V7 chord of 1:5/4:3/2:9/5 (20:25:30:36) results. This
chord is somewhat "softer" I think than the Pythagorean one. Of course
one can still use the Ptolemy tuning and use a m7 of 16/9 instead of
9/5. If we do that we obtain 1:5/4:3/2:16/9 (36:45:54:64) as
pitch/interval ratios for the V7 chord. But that also introduces m3s of
32/27 in addition to 6/5.
Post by Joey Goldstein
Is it possible to use a 4 digit frequency ratio (eg. 7:6:5:4) to
describe *all* the intervals in a JI tuned V7 chord?
If so, then what are those digits please?
What you're describing can be provided via a 7-limit (septimal) tuning.
Specifying a 4:5:6:7 (1:5/4:3/2:7/4) V7 chord defines all chord
interval (unison, M3, m3, P5, m7, d5) ratios wrt the root. Note that
when we use the harmonic (minor) 7th we get a softer-beating d5 of 7/5
(cf to 36/25 for example). (I didn't refer to 7/5 as a tritone since
strictly speaking a tritone is a M2^3 = A4 interval)
--
J. B. Wood e-mail: ***@hotmail.com
Joey Goldstein
2011-04-06 16:21:50 UTC
Permalink
Thanks guys, but I don't think that either of you are really getting the
scale or the chord I'm talking about.
You're both talking as if the ratio of the m7 on the V7 chord can be
adjusted to some other ratio than 16:9.
In the major key just intonation I'm talking about the b7 of V7 is
determined by the pitch of the root of IV, and the pitch of the root of
IV is determined by the root of IV being in a 3:2 relationship with the
tonic of the key.

My understanding, and I guess I could be wrong about this, is that
tuning the root of IV this way will automatically result in the ratio of
the m7 within the V7 chord being 16:9 and only 16:9.
Please correct me if that's wrong and let me know what the correct ratio
of this interval is.

My own calculations on this are based on a JI for A major.
With A110 as the tonic, I calculate the freq of D as being D146.668.
(110 div by 3 = 36.666666. 36.667 X 4 = 146.668.)
E will, of course, be tuned to E165.
(110 X 3 = 330. 330 div by 2 = 165.)
So the m7 above E165 will be D293.336.
(146.668 X 2 = 293.336.)
So the two pitches involved in this interval are
E165 and D293.336.
And that interval is at a freq ratio of 16:9.
(16 div by 9 = 1.778. 165 X 1.778 = 293.37.)

So, my main question, again, is:
Given a JI such as this, is there a 4-digit ratio that can describe the
intervals in *this* entire dom7 chord?
I.e. We know that its root 3rd and 5th are at 6:5:4.
When we add the b7, which is at 16:9 in relation to the chord's root,
what is the 4-digit ratio that correctly describes the entire chord?

It's not clear to me (see below) if Hans meant to answer this with
"36:45:54:64", or not.
Again, folks, as always, my math skills are *really* minimal, limited to
basic arithmetic I'm afraid.
So please keep any maths in your posts to a minimum.
It looks like Hans was talking about ways to multiply ratios, and even
that is beyond my math skills, unless it is explained to me.
Sorry.
---------

Actually, looking at Hans' explanation of how he arrived at 36:45:54:64
is beginning to make sense to me, but I can't understand how he
calculated the "least common denominators".
What does the symbol "^" mean?
[I can't even find it on my keyboard and had to paste it in from Hans'
post. lol]
At first I thought it meant "multiply by" because he wrote
2^2 = 4.
But then he wrote 3^2 = 9 which doesn't make sense.
??

And again, my other question was about the min 3rds contained in this chord.
They appear to be of different sizes from each other to me.
The ratio of the m3 between the chord's 3rd and its 5th, by definition,
will be 6:5.
But what is the ratio between this chord's 5th and it min 7th?
Based on Hans' 4-digit ratio of the entire chord, would it be 64:54?
That reduces to 32:27, but no further, right?

And I wasn't even thinking about the tritone of this chord, but based on
Hans' ratio it would be 64:45, which doesn't reduce at all, right?

The rest of Hans' 4-digit ratio seems totally plausible to me.
45:36 reduces to 5:4.
54:36 reduces to 3:2.
And 54:45 reduces to 6:5.
The common denominator of all three digits (36, 45, and 54) being 9.
And 64:36 reduces to 16:9 (common denominator being 2).

So, it looks like Hans' ratio is correct, even though I don't completely
understand how he calculated it.
Thanks Hans!

So, in a major key JI the V7 chord is several times more
complex/dissonant than the I IV or V triads.
Right?
Might this partially account for why it is that early CPP composers,
operating in just intonations and exploring the maj/min key system (in
contrast to the earlier modal system) for the first time, treated dom7
chords as being so dissonant as to *always* require resolution?
It also seems to me that equal temperament has actually softened the
dissonance of the dom7 chord somewhat, which may have helped pave the
way to things like jazz musicians treating dom7 chords as consonances.
Does that make any sense?
Or am I totally off-base and making assumptions that are simply incorrect?
--
Joey Goldstein
<http://www.joeygoldstein.com>
<http://homepage.mac.com/josephgoldstein/AudioClips/audio.htm>
joegold AT primus DOT ca
Hans Aberg
2011-04-06 20:29:38 UTC
Permalink
Post by Joey Goldstein
Thanks guys, but I don't think that either of you are really getting the
scale or the chord I'm talking about.
You're both talking as if the ratio of the m7 on the V7 chord can be
adjusted to some other ratio than 16:9.
There seems to be a variation on this interval. In addition, one gets
different Just major and minor scales:

If the Just major scale is constructed by requiring that the tonic,
dominant and subdominant major thirds are Just 4:5:6, then one of the
minor triad get out of tune. In C major, it is Dm, I recall. Similarly,
one can construct a Just minor scale by requiring its minor triads being
1:6/5:3/2 = 10:12:15, but then one of the major triads go out of tune.
This is described on the WP pages "Just intonation" and "Five-limit tuning".
Post by Joey Goldstein
In the major key just intonation I'm talking about the b7 of V7 is
determined by the pitch of the root of IV, and the pitch of the root of
IV is determined by the root of IV being in a 3:2 relationship with the
tonic of the key.
Let's compute this interval. Just major is in key C
Key C D E F G A B C'
Degree 1 2 3 4 5 6 7 8
Just major T t s T t T s
where
s = mj = 16/15
t = Mj = 10/9
T = MJ = 9/8

All major triads are in tune, so G, to D is 3/2. D to F is s = 16/15 and
t = 10/9, which is 32/27. And this latter and 3/2 is 16/9.
Post by Joey Goldstein
My understanding, and I guess I could be wrong about this, is that
tuning the root of IV this way will automatically result in the ratio of
the m7 within the V7 chord being 16:9 and only 16:9.
Please correct me if that's wrong and let me know what the correct ratio
of this interval is.
So in this position this is so - and it is the only dominant 7th within
the Just major scale.
Post by Joey Goldstein
My own calculations on this are based on a JI for A major.
With A110 as the tonic, I calculate the freq of D as being D146.668.
(110 div by 3 = 36.666666. 36.667 X 4 = 146.668.)
E will, of course, be tuned to E165.
(110 X 3 = 330. 330 div by 2 = 165.)
So the m7 above E165 will be D293.336.
(146.668 X 2 = 293.336.)
So the two pitches involved in this interval are
E165 and D293.336.
And that interval is at a freq ratio of 16:9.
(16 div by 9 = 1.778. 165 X 1.778 = 293.37.)
Given a JI such as this, is there a 4-digit ratio that can describe the
intervals in *this* entire dom7 chord?
I.e. We know that its root 3rd and 5th are at 6:5:4.
When we add the b7, which is at 16:9 in relation to the chord's root,
what is the 4-digit ratio that correctly describes the entire chord?
It's not clear to me (see below) if Hans meant to answer this with
"36:45:54:64", or not.
Yes.
Post by Joey Goldstein
Again, folks, as always, my math skills are *really* minimal, limited to
basic arithmetic I'm afraid.
So please keep any maths in your posts to a minimum.
It looks like Hans was talking about ways to multiply ratios, and even
that is beyond my math skills, unless it is explained to me.
So take this really easy. Somehow we got 36:45:54:64. Take away 64,
which is 36:45:54. Divide all numbers by their greatest common divisor
(gcd), which is 9, to get 4:5:6. So this part is the Just major chord.
And 64/36 = 16/9, so this means that the 64 in relation to the first 36
is the Just minor 7th under discussion.

Now compute frequencies. Use either of the forms 36:45:54:64 or
1:5/4:3/2:16/9. The latter is in fact easier.

If A2 = 110 Hz, then E3 = 110*3/2 = 165 Hz, so E2 = 165/2 = 82.5 Hz.
Then D3 = 82.5*16/9 = 146.667 Hz, which is what you got above, except
for the rounding.

Alternatively, one can use a table:

P1 M1 M2 P4 P5 M6 M7 P8
1/1 9/8 5/4 4/3 3/2 5/3 15/8 2/1
A B C'# D' E' F' G' A'

So if A2 = 110 Hz, D3 = 110*4/3 = 146.667 Hz.
Post by Joey Goldstein
Actually, looking at Hans' explanation of how he arrived at 36:45:54:64
is beginning to make sense to me, but I can't understand how he
calculated the "least common denominators".
It should have been the greatest common multiple, I think.
Post by Joey Goldstein
What does the symbol "^" mean?
Exponentiation. 2^3 = 2 three times = 2*2*2 = 8. 3^2 = 3 two times = 3*3
= 9.
Post by Joey Goldstein
[I can't even find it on my keyboard and had to paste it in from Hans'
post. lol]
It is ASCII. On a US keyboard, it is <shift>-6.
Post by Joey Goldstein
2^2 = 4.
But then he wrote 3^2 = 9 which doesn't make sense.
??
Multiply two times 3*3 = 9.
Post by Joey Goldstein
And again, my other question was about the min 3rds contained in this chord.
They appear to be of different sizes from each other to me.
Yes they are, 6/5 and the same value reduce by a syntonic comma 81/80.
Just major is uneven, due to two differently sized major seconds.
Post by Joey Goldstein
The ratio of the m3 between the chord's 3rd and its 5th, by definition,
will be 6:5.
But what is the ratio between this chord's 5th and it min 7th?
Based on Hans' 4-digit ratio of the entire chord, would it be 64:54?
That reduces to 32:27, but no further, right?
Right: 32 = 2^5 and 27 = 3^3, so they have no common prime number
factors. But here, ":" is not a ratio, but indicates a list of numbers
that can be altered by multiplication by the same number.
Post by Joey Goldstein
And I wasn't even thinking about the tritone of this chord, but based on
Hans' ratio it would be 64:45, which doesn't reduce at all, right?
Right: 64 = 2^6, and 45 = 3^2*5, which has no common prime number factors.
Post by Joey Goldstein
The rest of Hans' 4-digit ratio seems totally plausible to me.
45:36 reduces to 5:4.
54:36 reduces to 3:2.
And 54:45 reduces to 6:5.
The common denominator of all three digits (36, 45, and 54) being 9.
And 64:36 reduces to 16:9 (common denominator being 2).
So, it looks like Hans' ratio is correct, even though I don't completely
understand how he calculated it.
Thanks Hans!
You are welcome.
Post by Joey Goldstein
So, in a major key JI the V7 chord is several times more
complex/dissonant than the I IV or V triads.
Right?
You get beats among the partials which are a bit off low numbered
harmonic ratios. The 16/9 is off 7/4, so the 7th partial of the lower
note will produce beats with the 4th partial of the upper note. The
Upper minor triad is off 6/5, so it will produce beats between the 6
partial of the lower note and the 5th of the upper note. And so on. It
gets quite complex. A pair of ears might be helpful. :-)
Post by Joey Goldstein
Might this partially account for why it is that early CPP composers,
operating in just intonations and exploring the maj/min key system (in
contrast to the earlier modal system) for the first time, treated dom7
chords as being so dissonant as to *always* require resolution?
Yes, I think so. Likewise, the +6 in quarter-comma meantone or E31 is so
stable that the only chord they can resolve to is a major triad. So
therefore, since +6 is out of the diatonic scale, one of the few uses is
as a predominant.
Post by Joey Goldstein
It also seems to me that equal temperament has actually softened the
dissonance of the dom7 chord somewhat, which may have helped pave the
way to things like jazz musicians treating dom7 chords as consonances.
Does that make any sense?
Or am I totally off-base and making assumptions that are simply incorrect?
In E12, the M3 is off 5/4 by 13.686 cents and the m3 is off 6/5 by
15.641 cents (and the P5 is off 3/2 by 1.955 cents). So this makes the
E12 major and minor a bit unstable.

But if one can accept this instability in these chords to resolve
towards, the dominant should be more stable than the Just one using m7 16/9.

So early CPP composers may have resisted both the dominant 7th and
tempered tunings because of that instability. But as one accepts some
instability in the minor and minor chords, there is some improvement in
the dominant 7th.

So that seems a possible explanation.

Hans
Joey Goldstein
2011-04-06 21:07:16 UTC
Permalink
Thanks again Hans.
--
Joey Goldstein
<http://www.joeygoldstein.com>
<http://homepage.mac.com/josephgoldstein/AudioClips/audio.htm>
joegold AT primus DOT ca
Hans Aberg
2011-04-06 22:06:25 UTC
Permalink
Post by Joey Goldstein
Thanks again Hans.
You are welcome, Joey.

Hans
Bohgosity BumaskiL
2011-06-05 16:09:26 UTC
Permalink
Hans Aberg wrote: (...) 64:54:45:36 (...)

I got the same answer, although I was a bit troubled by 64:54 being
32:27 (pythagorean minor third), and not 16:6=8:3 (a perfect
eleventh). The question had a three-member ratio and a two-member
fraction, so working 16:6 in probably isn't possible. Mister Aberg
also mentioned that some books call 9:5 a minor seventh. I hav one
such book. That would make it simply 9:6:5:4, which looks like a more
stable chord, because all six combinations are listed here:
http://www.huygens-fokker.org/docs/intervals.html

On the other hand, in the thread about Tweaking Terry Riley's harp,
64:45 is listed, so a few non-qwerty instruments might be able to do
what Mister Goldberg wants. Lots of instruments can do 9:6:5:4. Go up
a major third, then up a minor third further, then up a fifth more.
_______
http://ecn.ab.ca/~brewhaha/Biology/Cocoa_Brazil.htm
Hans Aberg
2011-06-06 14:14:08 UTC
Permalink
Post by Bohgosity BumaskiL
I got the same answer, although I was a bit troubled by 64:54 being
32:27 (pythagorean minor third), and not 16:6=8:3 (a perfect eleventh).
The question had a three-member ratio and a two-member fraction, so
working 16:6 in probably isn't possible. Mister Aberg also mentioned
that some books call 9:5 a minor seventh. I hav one such book. That
would make it simply 9:6:5:4, which looks like a more stable chord,
http://www.huygens-fokker.org/docs/intervals.html
As in the discussion with Joey, the m7 16/9 shows up in the dominant 7th
of Just intonation:

The Just intonation major scale is constructed so that I, IV and V are
4:5:6 chords. So I-V is 3/2 and I-IV is 4/3, and therefore V-IV' is
2*(4/3)/(3/2) = 16/9.

Using 9/5 leads to a more stable chord, but is not the Just dominant
7th, though variable pitch instruments would probably use it instead.
The difference (9/5)/(16/9) = 81/80 is the syntonic comma, which can be
defined as the difference between the (lower) Just major third 5/4 and
the (higher) Pythagorean major third 81/64.

Whenever there is a small difference, a comma, when working with Just
intonation, there is a good chance it is this syntonic comma 81/80.

One can estimate it by working in E53, where the minor second m = 4, and
the major second M = 9, which approximates the Pythagorean tuning so
closely that it is impossible to hear the difference for simple
intervals. The small Just intonation major second JM = 8.

So, for example, the Pythagorean major third M3 = 2*9 = 18, and the Just
major third JM3 = 9 + 8 = 17. The difference M3 - JM3 = 18 - 17 = 1, so
since it is due to a difference between the 5- and 3- limits (Just and
Pythagorean), we would expect it to be a syntonic comma, which one then
can verify it is. If the difference would be all in the 3-limit, one
would instead expect a Pythagorean comma.

Hans
J.B. Wood
2011-06-06 17:39:51 UTC
Permalink
Post by Hans Aberg
As in the discussion with Joey, the m7 16/9 shows up in the dominant 7th
The Just intonation major scale is constructed so that I, IV and V are
4:5:6 chords. So I-V is 3/2 and I-IV is 4/3, and therefore V-IV' is
2*(4/3)/(3/2) = 16/9.
Using 9/5 leads to a more stable chord, but is not the Just dominant
7th, though variable pitch instruments would probably use it instead.
The difference (9/5)/(16/9) = 81/80 is the syntonic comma, which can be
defined as the difference between the (lower) Just major third 5/4 and
the (higher) Pythagorean major third 81/64.
Hello, Hans, and all. The JI scale you mentioned is the oft-cited
5-limit Ptolemy "diatonic syntonon" tuning. (There are many other
historical tunings of 3 and 5-limit diatonic JI scales). Since the V7
chord contains a m7 interval it can be constructed, as you point out, as
1:5/4:3/2:16/9 from the notes of this just major scale or as
1:5/4:3/2:9/5 if one uses the 6/5 m3 interval from that same scale.
Using C-E-G-Bb as an example V7 chord, if we use a G-Bb (Pythagorean) m7
of 16/9 we obtain a G-Bb (Pythagorean) m3 of 32/27 whereas with a C-Bb
m7 of 9/5 we obtain a much less harsh G-Bb of 6/5. A similar observation
can be made by using the E-Bb dim 5th (approx tritone) interval in this
V7 chord. Sincerely,
--
J. B. Wood e-mail: ***@hotmail.com
J.B. Wood
2011-06-06 18:21:26 UTC
Permalink
Post by J.B. Wood
Using C-E-G-Bb as an example V7 chord, if we use a G-Bb (Pythagorean) m7
of 16/9 we obtain a G-Bb (Pythagorean) m3 of 32/27 whereas with a C-Bb
m7 of 9/5 we obtain a much less harsh G-Bb of 6/5. A similar observation
can be made by using the E-Bb dim 5th (approx tritone) interval in this
V7 chord. Sincerely,
Ooops, a typo. I should've said: C-Bb (Pythagorean) m7 of 16/9...
--
J. B. Wood e-mail: ***@hotmail.com
Hans Aberg
2011-06-06 20:21:38 UTC
Permalink
Post by J.B. Wood
Post by Hans Aberg
As in the discussion with Joey, the m7 16/9 shows up in the dominant 7th
The Just intonation major scale is constructed so that I, IV and V are
4:5:6 chords. So I-V is 3/2 and I-IV is 4/3, and therefore V-IV' is
2*(4/3)/(3/2) = 16/9.
Using 9/5 leads to a more stable chord, but is not the Just dominant
7th, though variable pitch instruments would probably use it instead.
The difference (9/5)/(16/9) = 81/80 is the syntonic comma, which can be
defined as the difference between the (lower) Just major third 5/4 and
the (higher) Pythagorean major third 81/64.
The JI scale you mentioned is the oft-cited
5-limit Ptolemy "diatonic syntonon" tuning. (There are many other
historical tunings of 3 and 5-limit diatonic JI scales). Since the V7
chord contains a m7 interval it can be constructed, as you point out, as
1:5/4:3/2:16/9 from the notes of this just major scale or as
1:5/4:3/2:9/5 if one uses the 6/5 m3 interval from that same scale.
Using C-E-G-Bb as an example V7 chord, ...
A problem here is that the JM scale does not contain a Bb; the only one
is V7.
Post by J.B. Wood
...if we use a G-Bb (Pythagorean) m7
of 16/9 we obtain a G-Bb (Pythagorean) m3 of 32/27 whereas with a C-Bb
m7 of 9/5 we obtain a much less harsh G-Bb of 6/5. A similar observation
can be made by using the E-Bb dim 5th (approx tritone) interval in this
V7 chord.
But one can construct a Just minor scale in the same key by requiring i,
iv and v are all 1:6/5:3/2. Then the m7 interval is 9/5.

Hans
J.B. Wood
2011-06-07 10:40:00 UTC
Permalink
Post by Hans Aberg
A problem here is that the JM scale does not contain a Bb; the only one
is V7.
Hello, and although a Bb note would not exist in a diatonic major C
scale, the 6/5 m7 does exist as A-C, E-G and B-D in this tuning, which
was what I was trying to point out. So, yes, we would have to add a
chromatic(s) to this scale to get a 1:5/4:3/2:9/5 V7 chord(s).
As you also point out we can get Bb (and Eb and Ab) from a just minor
diatonic tuning. If we then combine both the just major and minor
tunings (and through in perhaps an F# and C#) we obtain a 12-tone JI
chromatic scale that, in addition to F-A-C-Eb, C-E-G-Bb and A-C#-E-G
chords, can provide C natural minor, C melodic minor, and C harmonic
minor scales. M7 and m7 chords are also available with this tuning.
Sincerely,
--
J. B. Wood e-mail: ***@hotmail.com
Hans Aberg
2011-06-07 18:11:47 UTC
Permalink
Post by J.B. Wood
Post by Hans Aberg
A problem here is that the JM scale does not contain a Bb; the only one
is V7.
Hello, and although a Bb note would not exist in a diatonic major C
scale, the 6/5 m7 does exist as A-C, E-G and B-D in this tuning, which
was what I was trying to point out.
In addition, ii does not have a P5 3/2.
Post by J.B. Wood
So, yes, we would have to add a
chromatic(s) to this scale to get a 1:5/4:3/2:9/5 V7 chord(s).
As you also point out we can get Bb (and Eb and Ab) from a just minor
diatonic tuning. If we then combine both the just major and minor
tunings (and through in perhaps an F# and C#) we obtain a 12-tone JI
chromatic scale that, in addition to F-A-C-Eb, C-E-G-Bb and A-C#-E-G
chords, can provide C natural minor, C melodic minor, and C harmonic
minor scales. M7 and m7 chords are also available with this tuning.
But one can make a combined Just major-minor scale with alternate scale
degrees.

Hans
LJS
2011-06-08 02:37:06 UTC
Permalink
Post by Hans Aberg
Post by J.B. Wood
Post by Hans Aberg
A problem here is that the JM scale does not contain a Bb; the only one
is V7.
Hello, and although a Bb note would not exist in a diatonic major C
scale, the 6/5 m7 does exist as A-C, E-G and B-D in this tuning, which
was what I was trying to point out.
In addition, ii does not have a P5 3/2.
Post by J.B. Wood
So, yes, we would have to add a
chromatic(s) to this scale to get a 1:5/4:3/2:9/5 V7 chord(s).
As you also point out we can get Bb (and Eb and Ab) from a just minor
diatonic tuning. If we then combine both the just major and minor
tunings (and through in perhaps an F# and C#) we obtain a 12-tone JI
chromatic scale that, in addition to F-A-C-Eb, C-E-G-Bb and A-C#-E-G
chords, can provide C natural minor, C melodic minor, and C harmonic
minor scales. M7 and m7 chords are also available with this tuning.
But one can make a combined Just major-minor scale with alternate scale
degrees.
Hans
You know, if you want to hear all the various tunings that don't quite
work in most contexts, you don't need to do any ratios or use any
programs. All you have to do is tune in to American Idol. You will
hear a different tuning on practically every tune that is preformed on
the show! The ear is capable of tolerating an amazing amount of
variation on ALL the notes. So you can build a scale using practically
any tuning and in the end, there it will eventually be. Right there on
your TV set in every episode.
LJS
J.B. Wood
2011-06-08 11:37:31 UTC
Permalink
Post by LJS
You know, if you want to hear all the various tunings that don't quite
work in most contexts, you don't need to do any ratios or use any
programs. All you have to do is tune in to American Idol. You will
hear a different tuning on practically every tune that is preformed on
the show! The ear is capable of tolerating an amazing amount of
variation on ALL the notes. So you can build a scale using practically
any tuning and in the end, there it will eventually be. Right there on
your TV set in every episode.
LJS
You nailed that one, LJ. (Where's someone like Herb Khaury when you
need him?) Sincerely,
--
J. B. Wood e-mail: ***@hotmail.com
LJS
2011-06-08 17:55:15 UTC
Permalink
Post by LJS
You know, if you want to hear all the various tunings that don't quite
work in most contexts, you don't need to do any ratios or use any
programs. All you have to do is tune in to American Idol. You will
hear a different tuning on practically every tune that is preformed on
the show! The ear is capable of tolerating an amazing amount of
variation on ALL the notes. So you can build a scale using practically
any tuning and in the end, there it will eventually be. Right there on
your TV set in every episode.
LJS
You nailed that one, LJ.  (Where's someone like Herb Khaury when you
need him?) Sincerely,
--
lol - and people say TV is a wasteland!
Bohgosity BumaskiL
2011-10-07 06:59:31 UTC
Permalink
Post by Hans Aberg
Post by J.B. Wood
Post by Hans Aberg
A problem here is that the JM scale does not contain a Bb; the only one
is V7.
Hello, and although a Bb note would not exist in a diatonic major C
scale, the 6/5 m7 does exist as A-C, E-G and B-D in this tuning, which
was what I was trying to point out.
In addition, ii does not have a P5 3/2.
Post by J.B. Wood
So, yes, we would have to add a
chromatic(s) to this scale to get a 1:5/4:3/2:9/5 V7 chord(s).
As you also point out we can get Bb (and Eb and Ab) from a just minor
diatonic tuning. If we then combine both the just major and minor
tunings (and through in perhaps an F# and C#) we obtain a 12-tone JI
chromatic scale that, in addition to F-A-C-Eb, C-E-G-Bb and A-C#-E-G
chords, can provide C natural minor, C melodic minor, and C harmonic
minor scales. M7 and m7 chords are also available with this tuning.
But one can make a combined Just major-minor scale with alternate scale
degrees.
Hans
1:5/4:3/2:9/5 == 20:25:30:36 ... It's a constant for V7 in any key,
and it is a simpler expression than four ratios; fewer numbers.

Bohgosity BumaskiL
2011-06-06 09:18:53 UTC
Permalink
Post by Joey Goldstein
Thanks guys, but I don't think that either of you are really getting
the scale or the chord I'm talking about.
You're both talking as if the ratio of the m7 on the V7 chord can be
adjusted to some other ratio than 16:9.
In the major key just intonation I'm talking about the b7 of V7 is
determined by the pitch of the root of IV, and the pitch of the root
of IV is determined by the root of IV being in a 3:2 relationship
with
the tonic of the key.
My understanding, and I guess I could be wrong about this, is that
tuning the root of IV this way will automatically result in the
ratio
of the m7 within the V7 chord being 16:9 and only 16:9.
Please correct me if that's wrong and let me know what the correct
ratio of this interval is.
My own calculations on this are based on a JI for A major.
With A110 as the tonic, I calculate the freq of D as being D146.668.
(110 div by 3 = 36.666666. 36.667 X 4 = 146.668.)
E will, of course, be tuned to E165.
(110 X 3 = 330. 330 div by 2 = 165.)
So the m7 above E165 will be D293.336.
(146.668 X 2 = 293.336.)
So the two pitches involved in this interval are
E165 and D293.336.
And that interval is at a freq ratio of 16:9.
(16 div by 9 = 1.778. 165 X 1.778 = 293.37.)
Given a JI such as this, is there a 4-digit ratio that can describe
the intervals in *this* entire dom7 chord?
I.e. We know that its root 3rd and 5th are at 6:5:4.
When we add the b7, which is at 16:9 in relation to the chord's root,
what is the 4-digit ratio that correctly describes the entire chord?
It's not clear to me (see below) if Hans meant to answer this with
"36:45:54:64", or not.
Again, folks, as always, my math skills are *really* minimal,
limited
to basic arithmetic I'm afraid.
So please keep any maths in your posts to a minimum.
It looks like Hans was talking about ways to multiply ratios, and even
that is beyond my math skills, unless it is explained to me.
Sorry.
---------
Thirty-six equals nine times four. You want a nine to also reprezent a
four. That is most easily done with thirty-six, so your answer is now
X:X:X:36. You also want the first X to be at sixteen to nine in
relation to thirty-six: 36*16/9=64. So now you hav 64:X:X:36. Since
you want thirty-six to reprezent four in relation to six and five, you
can use 36*6/4 to get the second member of the ratio: 54, and you can
use 36*5/4 to get the third member: 64:54:45:36.
Post by Joey Goldstein
Actually, looking at Hans' explanation of how he arrived at
36:45:54:64 is beginning to make sense to me, but I can't understand
how he
calculated the "least common denominators".
What does the symbol "^" mean?
[I can't even find it on my keyboard and had to paste it in from Hans'
post. lol]
2^2 = 4.
But then he wrote 3^2 = 9 which doesn't make sense.
??
It's almost universal in computer languajez to reprezent
exponentiation with SHIFT-6. In HTML, it is more understandable to
write <sup>2</sup>, sup meaning superscript. Wiki's use ^2 for squared
(making it look more familiar). Three squared equals (three times
three) equals nine.
Post by Joey Goldstein
And again, my other question was about the min 3rds contained in
this
chord. They appear to be of different sizes from each other to me.
The ratio of the m3 between the chord's 3rd and its 5th, by
definition, will be 6:5.
But what is the ratio between this chord's 5th and it min 7th?
Based on Hans' 4-digit ratio of the entire chord, would it be 64:54?
That reduces to 32:27, but no further, right?
Right. Both members of the ratio are exponents of different prime
numbers, so that is a reduced fraction.
Post by Joey Goldstein
And I wasn't even thinking about the tritone of this chord, but
based
on Hans' ratio it would be 64:45, which doesn't reduce at all,
right?
Right. Sixty-four is a power of two, and fourty-five does not hav a
factor of two, so that is a reduced fraction.
Post by Joey Goldstein
The rest of Hans' 4-digit ratio seems totally plausible to me.
45:36 reduces to 5:4.
54:36 reduces to 3:2.
And 54:45 reduces to 6:5.
The common denominator of all three digits (36, 45, and 54) being 9.
And 64:36 reduces to 16:9 (common denominator being 2).
So, it looks like Hans' ratio is correct, even though I don't
completely understand how he calculated it.
Thanks Hans!
Hopefully, I've provided enough information for you to answer
questions like this yourself. If I haven't, then maybe Hans will be
able to do it without Scala.
Post by Joey Goldstein
So, in a major key JI the V7 chord is several times more
complex/dissonant than the I IV or V triads.
Right?
I would not know how to go about calculating levels of dissonance,
and I am not sure that complexity is necessarily dissonant. Complexity
*probably* is dissonant. I doubt that complexity which fits is
dissonant.
In other words, out of context, some chords would not sound musical
at all. In the right context, it may be that nothing but complexity
fits.
Post by Joey Goldstein
Might this partially account for why it is that early CPP composers,
operating in just intonations and exploring the maj/min key system (in
contrast to the earlier modal system) for the first time, treated dom7
chords as being so dissonant as to *always* require resolution?
It also seems to me that equal temperament has actually softened the
dissonance of the dom7 chord somewhat, which may have helped pave the
way to things like jazz musicians treating dom7 chords as
consonances.
Does that make any sense?
Jazz musicians, especially if you include Barbershop in that category,
and I know many of them classify themselves that way for the peculiar
beats and syncopation, are among the first to stick with the _old_
standard of 9:5 for a minor seventh. If you reduce 9:5 by an octave,
you get 4.5:5, or 9:10, or a minor second. I just wrote a tune full of
minor seconds.
Post by Joey Goldstein
Or am I totally off-base and making assumptions that are simply incorrect?
It is grade nine math in Alberta, and lots of people want to forget
everything that happened to them and half of what they did in those
years, especially the math prof. :-) You are doing fine.
_______
http://ecn.ab.ca/~brewhaha/Biology/Cocoa_Brazil.htm
If a picture is worth a thousand words, then a good recipe is worth a
writer.
Bohgosity BumaskiL
2011-06-05 13:19:48 UTC
Permalink
Joey Goldstein wrote:
(...)
Post by Joey Goldstein
It can't be 16:13:11:9 because 11:9 does not reduce to 5:4, and 13:11
does not reduce to 6:5 and we know that the V triad is tuned to 6:5:4.
So what would the numbers be?
Notice that 36=9*4. If you want to reprezent sixteen in the same
chord, then you also hav to multiply sixteen by four. After that, it's
a matter of filling in the middle. 45=36*5/4, and 54=36*6/4.

64:54:45:36
_______
http://ecn.ab.ca/~brewhaha/Sound/yumday.mp3
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